# A projectile is shot at an angle of #pi/4 # and a velocity of # 2 m/s#. How far away will the projectile land?

I got

To give a full explanation of the calculation method proved too long. So I have given a summery of the method I used.

Determine the flight time by using

This is the product of the flight time and the mean downward velocity.

Once you've equated them, you'll have a quadratic that can be resolved by applying the standard form formula.

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To find the horizontal distance traveled by the projectile, you can use the formula:

Range = (initial velocity^2 * sin(2*θ)) / g

Where:

- initial velocity (v) = 2 m/s
- angle of launch (θ) = π/4 radians
- gravitational acceleration (g) = 9.8 m/s^2

Plugging in the values:

Range = (2^2 * sin(2*(π/4))) / 9.8

Range = (4 * sin(π/2)) / 9.8

Range = (4 * 1) / 9.8

Range ≈ 0.408 meters

Therefore, the projectile will land approximately 0.408 meters away.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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